diophantine analysis

精品项目网 2024-05-16 19:17:07

基本释义:

丢番图分析

网络释义

1)diophantine analysis,丢番图分析

2)diophantus,丢番图

3)diophantine equation of Egyptian fractions,单位分数丢番图方程

4)Diophantine equation,丢番图方程

5)diophantine equations,丢番图方程

6)diophantus equation,丢番图方程

用法和例句

In this paper,structured of generative function method and technique is introduced by finding the solution of a kind of diophantus equation,thus we introduce power series such as generative function to apply in combination probabicity.

通过求解一类丢番图方程解的个数,介绍了生成函数的构造方法和技巧,从而以幂级数作为生成函数,介绍了它在组合概率计算中的应用。

On the Diophantine equation x~p-1=Dy~n;

关于丢番图方程x~p-1=Dy~n

On the solution of the Diophantine equations x~2-2p=y~n;

关于丢番图方程x~2-2p=y~n的解

On the Diophantine equation(15n)~x+(112n)~y=(113n)~z;

关于丢番图方程(15n)~x+(112n)~y=(113n)~z

On the Diophantine equations x~4±y~6=z~2 and x~2+y~4=z~6;

关于丢番图方程x~4±y~6=z~2与x~2+y~4=z~6

When p is a odd prime and p ≠1 (mod 8), we get all solutions of diophantine equations ( x(x+1)(2x+1)=2p~ky~(2n) ) with elementary theory of number.

若p为奇素数,且p≠1(mod8)时,本文给出了丢番图方程x(x+1)(2x+1)=2pky2n的所有正整数解,并给出了Lucas猜想的一个简单证明。

With the help of the elementary theory of number and Fermat method of infinite descent,some necessary conditions have been proved provided that the Diophantine equations x 4+mx 2y 2+ny 4=z 2 has positive Integer solutions that fit (x,y) =1 m.

利用数论方法及Fermat无穷递降法 ,证明了丢番图方程x4 +mx2 y2 +ny4 =z2 在 (m ,n) =(± 6,-3 ) ,(6,3 ) ,(± 3 ,3 ) ,(-12 ,2 4) ,(± 12 ,-2 4) ,(± 6,15 ) ,(-6,-15 ) ,(3 ,6)仅有平凡整数解 ,并且获得了方程在 (-6,3 ) ,(12 ,2 4) ,(3 ,-6) ,(-6,3 3 )时的无穷多组正整数解的通解公式 ,从而完善了Aubry等人的结

Let p>3 be a prime integer prime,when the elementary grade method and the Diophantus Equation theories are used.

设p>3为素数,证明了丢番图方程x6-y6=2pz2无正整数解,证明了丢番图方程x6+y6=2pz2在p 1(mod24)时无正整数解,同时获得了方程在p≡1(mod24)时有正整数解的计算公式。

In this paper two theorems are given by using matrixvector description of polynomial multiplication, which are useful to resolve the Diophantus equation.

采用多项式乘积的矩阵-向量表示方法,证明了对求解丢番图方程极为有用的定理1和定理2,从丢番图方程的基本解法着手,给出了各种设计要求下的极点配置算法。

Diophantus OF ALEXANDRIA

丢番图(亚历山大里亚的)(活动时期250年)

Sequential and Parallel Algorithms for Solving Linear Diophantine Equations

求解线性丢番图方程(组)的串、并行算法

On the Diophantine Equation of a~x-b~(2y)=46~2;

丢番图方程a~x-b~(2y)=46~2的一解

Diophantine Equation x~3-y~6=pz~2 and Tijdeman Corijecture;

丢番图方程x~3-y~6=pz~2与Tijdeman猜想

On Integer Solution of A Diophantine Equation;

关于丢番图方程x~2-py~4=1

On the Diophantine Equation x~3±p~(3n)=Dy~2;

关于丢番图方程x~3+p~(3n)=Dy~2的讨论

About the Diophantine Equation X + mY4= Z;

关于丢番图方程x~4+my~4=z~4

On the Diophantine Equation x~3 ±5~6 =Dy~2;

关于丢番图方程x~3±5~6=Dy~2

On the Conjecture (I) of Diophantus Approximation;

关于丢番图逼近中的一个猜想(I)

On the Diophantine Equations X~5 ± X~3 = DY~3;

关于丢番图方程X~5±X~3=Dy~3

On the Diophantine Equation x~4+mx~2y~2+ny~4=z~2;

关于丢番图方程x~4+mx~2y~2+ny~4=z~2

On the Diophantine Equations x~2±y~4=z~3;

关于丢番图方程x~2±y~4=z~3

On the Diophantine Equations x(x+1)=Dy~4;

关于丢番图方程x(x+1)=Dy~4

On the Diophantine Equation (x~m-1)(x~(mn) -1)=y~2;

关于丢番图方程(x~m-1)(x~(mn)-1)=y~2

On the Diophantine Equations x_4±y_6=z_2;

关于丢番图方程x~4±y~6=z~2

On the Diophantine Equations x~3±y~6=z~2;

关于丢番图方程x~3±y~6=z~2的解

On the Sum of Equal Powers and Diophantine Equation S_5(x) =y~n;

关于幂和丢番图方程S_5(x)=y~n

On the Diophantine Equation x~6±y~6=pqDz~2;

关于丢番图方程x~6±y~6=pqDz~2

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