基本释义:

级数求和法

网络释义

1)summation of series,级数求和法

2)the summation for Fourier series,Fourier级数求和法

3)Extracting the Sum of Unlimited Progression,无穷级数求和法

4)summation of series,级数求和

5)mean summation for Fourier series,Fourier级数平均求和法

6)The Sum and Its Solution to Power Series,幂级数求和法例谈

用法和例句

In this paper, a method of difference in summation of series is presented.

提出了一种级数求和的差分方法,讨论了差分的相关概念与性质,并应用差分法求某一类数项级数的部分和。

new method of calculating summation of series is constructed by using a set of suitable wave functions in an infinite square potential well of one dimension.

利用一维无限深方势阱中一套适当的波函数，建立了一种新的级数求和方法。

The Series sum from n=1 to ∞(x~n) Applies in Solving Summation Function and Summation of Series

关于幂级数在求和函数及级数求和方面的应用

Summation to Calculate a Class Infinite Series by Using Residue Theorem;

应用留数定理计算一类级数求和问题

Differential Method Application in Solving Summation of Special Constant Series;

微分法在一类特殊常数项级数求和中的应用

Several Summation Formulas for q-Series by Bailey’s Lemma;

由Bailey引理得到的若干q-级数求和公式(英文)

Peculiar solutions to sequence of the maximal number and the sum of series;

求数列极限及级数和的几个特殊方法

In particular, by applying Abel summation method to obtain broad sense sum of pergence series,the calulation of summation was made from convergence series to pergence series.

用阿贝尔求和法求出发散级数的广义和,跨出了求和由收敛级数到发散级数的一步.

Abel's Lemma on Summation by Parts and q-Series Transformation and Summation Formulae

Abel分部求和法与q-级数变换及求和公式

Complex Analytic Function Utilized in Sum Function Evaluation of Trigonometric Progression;

利用复变解析函数求三角级数的和函数

The Abel Lemma on Summation by Parts and Classical Hypergeometric Series;

Abel分部求和法与经典超几何级数

Thoughts on Saudent Abitity in Computing Series Sum Using Power Series Properties;

对学生利用幂级数性质求数项级数和的能力的思考

Specification and technical requirements for oil immersed power transformers 500kV

GB/T16274-1996油浸式电力变压器技术参数和要求500kV级

Makes the world-class digital television brand is Haier's pursue and the goal!

打造世界级数字电视品牌是海尔的追求和目标！

A Elementary Method Summating the Series sum form n=1 to ∝(1/n~(2m));

级数sum form n=1 to ∝(1/n~(2m))的一种初等求和法

A Brief Discussion on how to Evaluate the Sum of Unlimited Progression;

无穷级数sum from k=1 to ∞(k~n.q~k)求和方法的探讨

The Sum of A series;

求级数sum from n=1to∞(1/(n~2))和的另一种方法

Exact solution of Burgers equation by trigonometric series and Maple

用三角级数和Maple软件求Burgers方程的精确解

Sets the Encryption level to one of Low, Medium or High. The function takes one parameter that specifies the Encryption Level: 0 = Low, 1 = Medium and 2 = High.

将加密级别设为低、中或高。函数要求一个指定加密级别的参数:0=低、1=中和2=高。

Sets the Encryption level to one of Low, Medium or High. The function takes one parameter that specifies the Encryption Level: 1 = Low, 2 = Medium and 3 = High.

将加密级别设为低、中或高。函数要求一个指定加密级别的参数:1=低、2=中和3=高。